How busy was the line
A shift board shows what share of the planned time the line was actually running.
- A whole-number percentage, rounded half up.
- Running longer than planned still reads as 100 — the board does not show more than full.
- No planned time means no percentage: return 0.
utilisationPercent(runMinutes: int, plannedMinutes: int) → int
C++ needs a compiler and Drill does not host one yet, so this page is the reference rather than an exercise: the problem, worked examples, and the solution in full. To type it out, the same problem runs in Python.
Where you start
int utilisationPercent(int runMinutes, int plannedMinutes) {
}Worked examples
| Call | Result |
|---|---|
utilisationPercent(420, 480) | 88 |
utilisationPercent(480, 480) | 100 |
utilisationPercent(500, 480) | 100 |
utilisationPercent(0, 480) | 0 |
Hint
Round first, then cap. Capping first hides the rounding.
Reference solution in C++
int utilisationPercent(int runMinutes, int plannedMinutes) {
if (plannedMinutes <= 0 || runMinutes <= 0) return 0;
int pct = (runMinutes * 100 + plannedMinutes / 2) / plannedMinutes;
return std::min(100, pct);
}