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Overall equipment effectiveness

mediumproductionMathC++

OEE multiplies three percentages together into one number that plant managers compare across lines.

oeeScore(availability: int, performance: int, quality: int) → int

C++ needs a compiler and Drill does not host one yet, so this page is the reference rather than an exercise: the problem, worked examples, and the solution in full. To type it out, the same problem runs in Python.

Solve it in Python →

Where you start

int oeeScore(int availability, int performance, int quality) {
    
}

Worked examples

CallResult
oeeScore(90, 95, 99)85
oeeScore(100, 100, 100)100
oeeScore(0, 100, 100)0
oeeScore(150, 100, 100)100

Hint

Clamp all three first, then multiply and divide by 10000 — adding 5000 before the divide rounds it.

Reference solution in C++
int oeeScore(int availability, int performance, int quality) {
    auto c = [](int v) { return std::max(0, std::min(100, v)); };
    return (c(availability) * c(performance) * c(quality) + 5000) / 10000;
}

The same problem in another language

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