Split a bill without losing a kuruş
A table of friends splits the bill. The app has to hand out whole minor units that add back to exactly what was charged.
- Everyone pays the same, except that the remainder is handed out one unit at a time, starting from the first person.
- The shares must add back to the total exactly.
- Nobody at the table, or a negative total, gives an empty list.
splitBill(total: int, people: int) → list<int>
C++ needs a compiler and Drill does not host one yet, so this page is the reference rather than an exercise: the problem, worked examples, and the solution in full. To type it out, the same problem runs in Python.
Where you start
std::vector<int> splitBill(int total, int people) {
}Worked examples
| Call | Result |
|---|---|
splitBill(1000, 3) | std::vector<int>{334, 333, 333} |
splitBill(1000, 4) | std::vector<int>{250, 250, 250, 250} |
splitBill(10, 4) | std::vector<int>{3, 3, 2, 2} |
splitBill(0, 3) | std::vector<int>{0, 0, 0} |
Hint
Base share is total / people. The first (total % people) people pay one more.
Reference solution in C++
std::vector<int> splitBill(int total, int people) {
if (people <= 0 || total < 0) return {};
int base = total / people, extra = total % people;
std::vector<int> shares;
for (int i = 0; i < people; i++) shares.push_back(i < extra ? base + 1 : base);
return shares;
}