Problems › TypeScript › payments
Split a bill without losing a kuruş
A table of friends splits the bill. The app has to hand out whole minor units that add back to exactly what was charged.
- Everyone pays the same, except that the remainder is handed out one unit at a time, starting from the first person.
- The shares must add back to the total exactly.
- Nobody at the table, or a negative total, gives an empty list.
splitBill(total: int, people: int) → list<int>
Where you start
function splitBill(total: number, people: number): number[] {
}Worked examples
| Call | Result |
|---|---|
splitBill(1000, 3) | [334,333,333] |
splitBill(1000, 4) | [250,250,250,250] |
splitBill(10, 4) | [3,3,2,2] |
splitBill(0, 3) | [0,0,0] |
Hint
Base share is total / people. The first (total % people) people pay one more.
Reference solution in TypeScript
function splitBill(total: number, people: number): number[] {
if (people <= 0 || total < 0) return [];
const base = Math.floor(total / people);
const extra = total % people;
const shares: number[] = [];
for (let i = 0; i < people; i++) shares.push(i < extra ? base + 1 : base);
return shares;
}