Problems › TypeScript › games
Score a word by letter positions
A word game scores each letter by its position in the alphabet: a is 1, b is 2, and so on up to z is 26.
- Each lowercase letter a-z adds its position (a=1, b=2, ..., z=26).
- Characters that are not lowercase letters are ignored.
- An empty string scores zero.
wordScore(word: string) → int
Where you start
function wordScore(word: string): number {
}Worked examples
| Call | Result |
|---|---|
wordScore("abc") | 6 |
wordScore("hello") | 52 |
wordScore("") | 0 |
wordScore("a") | 1 |
Hint
Subtract the character code of a from each letter to get its value.
Reference solution in TypeScript
function wordScore(word: string): number {
let sum = 0;
for (let i = 0; i < word.length; i++) {
const c = word.charCodeAt(i);
if (c >= 97 && c <= 122) sum += c - 96;
}
return sum;
}