Problems › TypeScript › scheduling
Labour cost for the roster
A shift costs its staffed hours at ratePerHour (minor units per hour). Hours come from minute spans, prorated exactly.
- Pay = minutes ÷ 60 × rate, rounded down to whole minor units.
- A shift that lasts zero minutes costs nothing.
labourCost(shifts: list<Shift>, ratePerHour: int) → int
Where you start
function labourCost(shifts: Shift[], ratePerHour: number): number {
}Worked examples
| Call | Result |
|---|---|
labourCost([{"start":480,"end":900},{"start":900,"end":1080}], 2000) | 20000 |
labourCost([{"start":0,"end":30}], 2000) | 1000 |
labourCost([{"start":0,"end":0}], 5000) | 0 |
labourCost([], 1000) | 0 |
Hint
Sum (end - start) × rate, then divide by 60 once.
Reference solution in TypeScript
function labourCost(shifts: Shift[], ratePerHour: number): number {
let mins = 0;
for (const s of shifts) mins += s.end - s.start;
return Math.floor((mins * ratePerHour) / 60);
}