Good parts per run cycle
Each cycle a press makes partsPerCycle units and chips away scrapPerCycle of them. Count the good units over the whole run.
- Each cycle yields partsPerCycle minus scrapPerCycle good units.
- The good units are never negative — if scrap matches or beats output the cycle yields zero.
- The total is good units times the number of cycles.
cycle_output(cycles: int, parts_per_cycle: int, scrap_per_cycle: int) → int
Where you start
def cycle_output(cycles: int, parts_per_cycle: int, scrap_per_cycle: int) -> int:
Worked examples
| Call | Result |
|---|---|
cycle_output(10, 5, 1) | 40 |
cycle_output(0, 5, 1) | 0 |
cycle_output(5, 3, 3) | 0 |
cycle_output(5, 3, 5) | 0 |
Hint
Clamp the per-cycle good count at zero, then multiply by the cycles.
Reference solution in Python
def cycle_output(cycles: int, parts_per_cycle: int, scrap_per_cycle: int) -> int:
net = max(0, parts_per_cycle - scrap_per_cycle)
return cycles * net