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The middle of the list

mediumpatternsSortingArraysMathJava

A dashboard shows a campaign’s typical daily spend, and “typical” is whatever lands in the middle once the days are sorted.

medianOf(values: list<int>) → float

Java needs a compiler and Drill does not host one yet, so this page is the reference rather than an exercise: the problem, worked examples, and the solution in full. To type it out, the same problem runs in Python.

Solve it in Python →

Where you start

double medianOf(List<Integer> values) {
    
}

Worked examples

CallResult
medianOf(Main.<Integer>ls(3, 1, 2))2.0
medianOf(Main.<Integer>ls(1, 2))1.5
medianOf(Main.<Integer>ls(5))5.0
medianOf(Main.<Integer>ls(5, 1, 4, 2))3.0

Hint

Sort a copy, not the caller’s list, then look at the middle pair or single value.

Reference solution in Java
double medianOf(List<Integer> values) {
    List<Integer> xs = new ArrayList<>(values);
    Collections.sort(xs);
    int n = xs.size();
    if (n == 0) return 0.0;
    int mid = n / 2;
    return n % 2 == 1 ? xs.get(mid) : (xs.get(mid - 1) + xs.get(mid)) / 2.0;
}

The same problem in another language

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