Are these two an anagram
A word game checks whether one phrase uses exactly the same letters as another.
- Case does not matter.
- Whitespace is ignored entirely.
- Everything else — digits, punctuation — counts as a character that has to match.
- Two empty phrases are an anagram of each other.
isAnagram(text: string, other: string) → bool
Java needs a compiler and Drill does not host one yet, so this page is the reference rather than an exercise: the problem, worked examples, and the solution in full. To type it out, the same problem runs in Python.
Where you start
boolean isAnagram(String text, String other) {
}Worked examples
| Call | Result |
|---|---|
isAnagram("Listen", "Silent") | true |
isAnagram("a b", "ba") | true |
isAnagram("hello", "world") | false |
isAnagram("abc", "ab") | false |
Hint
Strip and lowercase both, then compare the sorted characters, or count them.
Reference solution in Java
boolean isAnagram(String text, String other) {
char[] a = text.toLowerCase().replaceAll("\\s+", "").toCharArray();
char[] b = other.toLowerCase().replaceAll("\\s+", "").toCharArray();
Arrays.sort(a);
Arrays.sort(b);
return Arrays.equals(a, b);
}