Average monthly figures for a year
Twelve monthly totals summarise a year. Report the average monthly figure, dropping the fractional minor unit.
- The list always carries twelve whole entries for a real year.
- Average is the total divided by 12, rounded down.
- A list with fewer than twelve entries is not a full year: return 0.
yearlyAverage(monthlyTotals: list<int>) → int
Go needs a compiler and Drill does not host one yet, so this page is the reference rather than an exercise: the problem, worked examples, and the solution in full. To type it out, the same problem runs in Python.
Where you start
func yearlyAverage(monthlyTotals []int) int {
}Worked examples
| Call | Result |
|---|---|
yearlyAverage([]int{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1}) | 1 |
yearlyAverage([]int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}) | 6 |
yearlyAverage([]int{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}) | 0 |
yearlyAverage([]int{100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100}) | 100 |
Hint
Guard the length, sum the entries, divide by twelve.
Reference solution in Go
func yearlyAverage(monthlyTotals []int) int {
if len(monthlyTotals) < 12 {
return 0
}
sum := 0
for _, v := range monthlyTotals {
sum += v
}
return sum / 12
}