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Machine uptime per thousand

easymachinesMathGo

Maintenance reports uptime as parts per thousand so a single line reads as 993 instead of a harder-to-compare 99.3%.

uptimePermille(upHours: int, downHours: int) → int

Go needs a compiler and Drill does not host one yet, so this page is the reference rather than an exercise: the problem, worked examples, and the solution in full. To type it out, the same problem runs in Python.

Solve it in Python →

Where you start

func uptimePermille(upHours int, downHours int) int {
	
}

Worked examples

CallResult
uptimePermille(1000, 0)1000
uptimePermille(993, 7)993
uptimePermille(750, 250)750
uptimePermille(3, 1)750

Hint

upHours * 1000 / total — but a total of zero is a special case that must come first.

Reference solution in Go
func uptimePermille(upHours int, downHours int) int {
	if upHours+downHours == 0 {
		return 1000
	}
	return upHours*1000 / (upHours + downHours)
}

The same problem in another language

More machines problems in Go