Extra pay for overnight hours
Hours between 22:00 and 06:00 carry a premium: each premium hour earns premiumPerHour on top of the base. Compute the added pay for one shift.
- The premium band is [22:00, 24:00) plus [00:00, 06:00), on the minute.
- A shift is described by start and finish minutes past midnight; a finish earlier than start means the shift crosses midnight.
- Return only the added pay: premium minutes ÷ 60 × premiumPerHour, rounded down.
nightPremium(start: int, finish: int, premiumPerHour: int) → int
Go needs a compiler and Drill does not host one yet, so this page is the reference rather than an exercise: the problem, worked examples, and the solution in full. To type it out, the same problem runs in Python.
Where you start
func nightPremium(start int, finish int, premiumPerHour int) int {
}Worked examples
| Call | Result |
|---|---|
nightPremium(1320, 1380, 3000) | 3000 |
nightPremium(360, 420, 1000) | 0 |
nightPremium(1260, 1440, 1000) | 2000 |
nightPremium(0, 120, 1000) | 2000 |
Hint
Split the shift against the two half-open bands; a crossing shift spans [start, 1440) plus [0, finish).
Reference solution in Go
func nightPremium(start int, finish int, premiumPerHour int) int {
if start == finish {
return 0
}
mins := func(x, y int) int {
if x < y {
return x
}
return y
}
maxs := func(x, y int) int {
if x > y {
return x
}
return y
}
overlap := func(a, b, lo, hi int) int {
v := mins(b, hi) - maxs(a, lo)
if v < 0 {
v = 0
}
return v
}
var minutes int
if start < finish {
minutes = overlap(start, finish, 0, 360) + overlap(start, finish, 1320, 1440)
} else {
minutes = overlap(start, 1440, 1320, 1440) + overlap(0, finish, 0, 360)
}
return minutes * premiumPerHour / 60
}